Matematika mohon bisa disertakan penjelasan. Soal terlampir digambar terima kasih​

mohon bisa disertakan penjelasan. Soal terlampir digambar terima kasih​

Penjelasan dengan langkah-langkah:

[tex] = \lim \limits_{x \to \infty } \frac{3 {x}^{2} + x + 2}{ \sqrt{2 {x}^{4} + {x}^{3} + {x}^{2} - 5} } [/tex]

[tex] = \lim \limits_{x \to \infty } \frac{3 + \frac{1}{x} + \frac{2}{ {x}^{2} } }{ \sqrt{2 + \frac{1}{x} + \frac{1}{ {x}^{2} } - \frac{5}{ {x}^{4} } } } \times \frac{ {x}^{2} }{ {x}^{2} } [/tex]

[tex] = \lim \limits_{x \to \infty } \frac{3 + \frac{1}{x} + \frac{2}{ {x}^{2} } }{ \sqrt{2 + \frac{1}{x} + \frac{1}{ {x}^{2} } - \frac{5}{ {x}^{4} } } } [/tex]

[tex] = \frac{3 + \frac{1}{ \infty } + \frac{2}{ { \infty }^{2} } }{ \sqrt{2 + \frac{1}{ \infty } + \frac{1}{ { \infty }^{2} } - \frac{5}{ { \infty }^{4} } } } [/tex]

[tex] = \frac{3 + 0 + 0}{ \sqrt{2 + 0 + 0 - 0} } [/tex]

[tex] = \frac{3}{ \sqrt{2} } [/tex]

[tex] = \frac{3 \sqrt{2} }{2} [/tex]

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